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Singly Circular Linked List - Delete node from the specific position.cpp
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Singly Circular Linked List - Delete node from the specific position.cpp
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#include <iostream>
using namespace std;
struct NODE {
int data;
NODE *next;
};
NODE *head, *tail, *temp;
void add(int value){
if(head == NULL){
head = tail = new NODE;
head->data = value;
head->next = tail;
} else {
tail->next = new NODE;
tail = tail->next;
tail->data = value;
tail->next = head;
}
}
int deleteAt(int position){
bool status = true;
NODE *prev;
temp = head;
for(int i = 1; i < position; i++){
prev = temp;
temp = temp->next;
if(temp == head){
temp = 0;
break;
}
}
if(temp == 0 || position <= 0){
cout << "The position [" << position << "] is invalid!" << endl;
return false;
} else {
if(temp == head){
if(head->next == head){
head = tail = 0;
} else {
head = temp->next;
tail->next = head;
}
} else {
prev->next = temp->next;
if(temp == tail) tail = prev;
}
delete temp;
return true;
}
}
bool print(NODE *ref){
if(ref == 0){
cout << "[EMPTY LIST]" << endl;
return false;
} else {
do {
cout << ref->data;
ref = ref->next;
if(ref != head) cout << " => ";
} while(ref != head);
cout << endl;
return true;
}
}
int main(){
add(10);
add(20);
add(30);
add(40);
add(50);
add(60);
add(70);
deleteAt(1);
deleteAt(3);
deleteAt(5);
print(head);
}